\r\n1.a\r\n 2.a\r\n 3.a\r\n 4.a\r\n 2.b\r\n 2.c\r\n 3.a\r\n 3.b\r\n 4.a\r\n\r\n
Sure, there are 2 3.a's out there. But it is easy to figure out which 2.? a 3.a is actually associated with.
\r\n\r\nCheers,\r\nBen
Link to parent post.
- (Silverlock)
- (11)
- Oct. 9, 2002, 11:45:42 PM EDT
Noted.
- (admin)
- (10)
- Oct. 10, 2002, 12:06:25 AM EDT
So I have given you a challenging exercise.
- (Silverlock)
- Oct. 10, 2002, 12:16:24 AM EDT
Possible alternate solution
- (ben_tilly)
- (8)
- Oct. 10, 2002, 06:44:26 AM EDT
I'm almost afraid to say this
- (drewk)
- (2)
- Oct. 10, 2002, 08:40:22 AM EDT
NOOOOOOOOOO!!!!! RUNAWAY! RUN-A-WAY!!!
- (folkert)
- (1)
- Oct. 10, 2002, 09:05:22 AM EDT
What you almost need is a JS solution.
- (static)
- Oct. 11, 2002, 12:21:38 AM EDT
Another alternate solution...
- (admin)
- (4)
- Oct. 10, 2002, 10:49:43 AM EDT
That helps, but ...
- (drewk)
- (3)
- Oct. 10, 2002, 11:45:15 AM EDT
Oh, don't worry...
- (admin)
- Oct. 10, 2002, 11:48:48 AM EDT
The problem with this:
- (admin)
- (1)
- Oct. 12, 2002, 10:03:50 PM EDT
How about:
- (ben_tilly)
- Oct. 13, 2002, 07:13:23 AM EDT