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New If you use a Karnaugh map, you'll see you're OK.
[link|http://www.ee.surrey.ac.uk/Projects/Labview/minimisation/karnaugh.html|Karnaugh map]. It's a two dimensional representation of a truth table.

The "sum of products" form is the easiest for filling out Karnaugh maps.

Using your first expression but ignoring the outer negation:

    a' a

b'  0  1
b   1  1

negating flips all bits

    a' a

b'  1  0
b   0  0


So, indeed it's a'b'.
Alex

"Propaganda does not deceive people; it merely helps them to deceive themselves." -- Eric Hoffer
Expand Edited by a6l6e6x Dec. 3, 2003, 03:56:56 PM EST
New Speaking of which
there's [link|http://www.embedded.com/showArticle.jhtml?articleID=16100908|A primer on Karnaugh maps] over on Embedded Systems that might be of interest.
Expand Edited by ChrisR Dec. 3, 2003, 03:41:29 PM EST
New Speaking of which^2
that's part 2 of the assignment:)
--\n-------------------------------------------------------------------\n* Jack Troughton                            jake at consultron.ca *\n* [link|http://consultron.ca|http://consultron.ca]                   [link|irc://irc.ecomstation.ca|irc://irc.ecomstation.ca] *\n* Kingston Ontario Canada               [link|news://news.consultron.ca|news://news.consultron.ca] *\n-------------------------------------------------------------------
     Boolean algebra - (jake123) - (7)
         b' == not b ? -NT - (Arkadiy) - (1)
             Yes. -NT - (jake123)
         Re: Boolean algebra - (Arkadiy) - (1)
             Well, it was my leading candidate - (jake123)
         If you use a Karnaugh map, you'll see you're OK. - (a6l6e6x) - (2)
             Speaking of which - (ChrisR) - (1)
                 Speaking of which^2 - (jake123)

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